Hi team
Quick question about 947 0X5B[bit6],could you help to explain what does this mean?
BR,
Joey
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Hi team
Quick question about 947 0X5B[bit6],could you help to explain what does this mean?
BR,
Joey
Hi Joey,
This bit basically performs the swap for example SER 947 PORT0 -> DES 948 PORT1 and SER 947 PORT1 -> DES 948 PORT0.
Hope this helps. Let me know if you have any questions.
Aaron
Hi. Aaron,
If I want to link 947 Dout1+/- to 948 RIN0+/-, and 947 Dout0+/- and 948 RIN0+/- NC, how to config the register?
Hi Aaron
1.why have to swap on 948 side? If so , what's the function of 947 0x5B?
2.Please also tell me how to config 947 or 948 for the below application?
Thank you Aaron~
Hi Joey,
Both 947 and 948 are capable of swapping the port. The 0x5B is the control register. If you want to swap the port per your diagram, you may use the register 0x5A[5:4] = b'10.
Aaron
Hi,Aaron,
Thank you for the explain,
Back to the beginning question: what does the 947 0X5B[bit6] mean?
Hi Joey,
If you are in single mode and you want to use channel 1 instead of channel 0, then you set 0x5A[5:4] = b'10
For dual mode is when you use the swap bits in 0x5B: 947 PORT0 -> 948 PORT1 and 947 PORT1 -> 948 PORT0.
Hope this helps. Let me know if you have further questions.
Aaron