This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

TCAN1044AEV-Q1: CSPLIT

Part Number: TCAN1044AEV-Q1

Hi team,

 

When using split termination with TCAN1044AEV-Q1, how can we calculated CSPLIT value?

SLLA270 mentions CSPLIT=4.7nF with 1.1Mbps. How can we determine CSPLIT when the data rate is 4Mbps with RL=120ohm?

 

Best regards,

Kurumi

  • Hi Kurumi,

    I believe calculating the recommended split capacitance comes from the equation in figure 10 in SLLA270,

    We can re-arrange the equation to say CL = 1 / (2*pi*R*fc). Multiply CL, divide by fc. 

    A key idea to note in this application note is that the cutoff frequency fc is measured in Hz. If we desire a 1.1Mbps CAN signal, this means we are operating about 1.1Mbps / 2 = 550 kHz with termination of R = 60ohm, the low-pass filter equation becomes the following.

    CL = 1 / (2*pi*60*550kHz) = ~4.823 nF. 

    Choose standard capacitor sizing of 4.7 nF. 

    Now with the customer requirements, is RL the size of each split resistor (2 x 120 ohm resistors), or is it 60ohm and 60hm like figure 10? 

    I can do the calculation for both cases. 

    fc = 4Mbps / 2 = 2MHz

    RL = 120 ohm

    CL = 1 / (2*pi*120*2MHz) = ~ 0.663 nF

    fc = 4Mbps / 2 = 2MHz

    RL = 60 ohm

    CL = 1 / (2*pi*60*2MHz) = ~1.33 nF

    Regards,

    Tyler

  • Hi Tyler,

    Thank you so much for your detailed explanations. I understood.