TCAL6416: Output timing

Register accesses are done in bytes. As shown in figure 8-9, each byte immediately affects the corresponding eight output pins.

What do you mean with "9pin"? Pin number 9 is named P05 or GND, depending on the package. The next pin after P07 is P10.

Section 8.6.4.1 of the datasheet says:

After sending data to one register, the next data byte is sent to the other register in the pair (see Figure 8-9 and Figure 8-10). For example, if the first byte is sent to Output Port 1 (register 3), the next byte is stored in Output Port 0 (register 2).

Hi TATSU,

I think what you are touching is the way the device reads/writes consecutive data.

When you conduct a successful read of port 0 data, the next data byte read will be the data found in port 1. The number of consecutive reads can potentially be unlimited for this device until a NACK condition is issued by the master/controller device followed by a stop condition. 

Regards,

Tyler

The eight pins from P00 to P07 are port 0. The eight pins from P10 to P17 are port 1.

It is not possible to change all sixteen bits at the same time; as shown in figure 8-9, there is a delay of nine I²C cycles (22.5 µs at 400 kHz) between the two ports.

If that delay is too large, you can use two cascaded SN74xx595 shift registers; they would be controlled with SPI, not I²C.