TUSB4041I: USB_VBUS Pin Resistor Divider Operation and Applicability of TUSB4041 in PD Environments (9 V / 20 V)

Guru 12155 points
Part Number: TUSB4041I

Tool/software:

Hi,

As I understand, the TUSB4041 is a USB 2.0 Hub designed for a 5 V VBUS environment. However, it should still be usable in a USB Power Delivery system where VBUS may rise to 9 V or 20 V. In such cases, the higher VBUS voltages are negotiated and protected by the PD controller, and the TUSB4041’s USB_VBUS pin must always receive the signal through a resistor divider.

According to the datasheet’s recommended circuit (90.9 kΩ / 10 kΩ divider), this results in approximately 0.45 V at USB_VBUS when VBUS = 5 V, about 0.82 V when VBUS = 9 V, and about 1.82 V when VBUS = 20 V. All of these values are below the absolute maximum rating of 3.6 V, so there is no risk of damage. However, they are outside the recommended operating condition of around 1.155 V (typ), with the 1.82 V at 20 V being notably higher than the typical target. My current understanding is that this is considered “outside the recommended operating condition but still functional.”

Could you please confirm if this understanding is correct — namely, that TUSB4041 can still be used in a PD environment with 9 V or 20 V, provided that a resistor divider is used, while noting that the resulting USB_VBUS voltage may fall outside the recommended range and should be taken into account in the design?

Best regards,

Conor

  • HI Conor:

      Do you have fixed supply on board ? like 5V or 3V?

      You can connect USB_VBUS pin to fixed supply with voltage divider to avoid 20v issue, 1.155 V (typ) is max voltage  allowed  on this pin.

    Best

    Brian