Please let me know below about Fail safe of AM26LV32E.
The Fail-safe circuit of AM26LV32E is considered to be the following.
VA-VB=[3.3/(200k+5k+200k+5k+221)]×(5k+5K+221) ≒80mV
VA-VB=[3.3/(200k+5k+200k+5k)]×(5k+5K) ≒80mV
In the upper calculation, I think that VID=200mV is not securable.
Is my calculation method wrong?
Moreover, do intend to terminated=OPEN?
Best regards,
Satoshi