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TL16CP754CIPM Questions

Kevin Hsieh1
Prodigy 80 points

1，波特率容忍
競爭對手= -4〜5％。
TL16CP754 = -3.6〜0％（NG）。
2。我們通過減少除數做實驗。但公差不改變。這僅僅是感動。請附圖！
3。取16xBaud（38400 * 16）=（18.432M / 4）X 1 /除數，例如，什麼是我們的公差為傳入的 ​​數據傳輸速率？

  • 0
    TI__Mastermind 21811 points

    Hi Kevin,

    I am going to move your question to the Consumer and Computing forum so that it can get the proper support and visibility. They should be able to address you question.

     

    In addition I am pasting a translated version of your question below:

    Baud rate tolerance
    Competitors = -4~5%.
    TL16CP754 = -3.6~0% (NG).
    2. We do experiments by reducing the divisor. However, the tolerance is not changed. This is just moved. Please drawings!
    3. Take 16xBaud (38400 * 16) = (18.432M / 4) X 1 / divisor, for example, what we tolerances for incoming data transfer rate?

    Thanks!

     

    John