Hello,
Could you please let me know the calculation method of IIH and IIL?
If Vcc=5V and VIH=2V, Is IIH (5V-2V)/(200kΩ+500Ω) = 15uA ?
I think that this calculation is wrong due to the datasheet specification is -30uA(typ).
Best Regards,
Ryuji Asaka