Hello,
Our customer use the SN65DSI84.
The customer will use the device with 0.9V LVDS common voltage.
It is mentioned the resister configuration for 0.9V common voltage
on the test condition of the electrical characteristics as follows.
0x19 . 6 = 1 :0.9V chA
0x19 . 4 = 1 :0.9V chB
0x1B . 6 = 1 : ? cannot find
0x1B . 4 = 1 : chA adjust
I think that the (0x1B . 6) is (0x1B . 0) actually. Is it right?
Best Regards,
Naoki Aoyama
