Supply current on TRS202E

Izumi Maruyama

Other Parts Discussed in Thread: TRS202E

The d/s for the TRS202E says the supply current as ICC is 8mA typ and 15mA max at VCC = 5V, no load but not sure how measured the current in detail.

Could you explain the measured method?

I was tried to measure the current then got following result. (VCC = 5V, room temp)

RIN1/2 are open as internal pull-downs are effective & DIN1/2 are connected to VCC or GND: 0.57mA

RIN1 is connected to VCC, RIN2 is open & DIN1/2 are connected to VCC or GND: 1.46mA

RIN1 is open, RIN2 is connected to VCC & DIN1/2 are connected to VCC or GND: 1.46mA

RIN1/2 are connected to VCC & DIN1/2 are connected to VCC or GND: 2.35mA

I know RIN1/2 are RS232C level input so need to feed like -10V or +10V but in such case the input current of RIN1/2 are increase to drive the internal pull-down resister but no change ICC as current on VCC. Then I’m very confusing how measure the ICC correctly.

Best regards,

Izumi Maruyama

over 8 years ago

0 Ron Michallick over 8 years ago

TI__Guru**** 164746 points

Izumi,

Are the charge pump capacitors installed per figure 5 in data sheet?

0 Izumi Maruyama over 8 years ago in reply to Ron Michallick

TI__Intellectual 1350 points

Hi Ronald,

Yes, of course I’m attached the capacitors to follow the figure 5.

I think the voltage convertor as to make the RS232C level voltage rails do not consume much current if there is no load. So it maybe 0.5mA so. So I’m not sure where consume 8mA typ current in a static state. Is the 8mA is consume at a switching state? Anyway I want to know how you got the 8mA current in detail.

Best regards,

Izumi Maruyama

0 Ron Michallick over 8 years ago in reply to Izumi Maruyama

TI__Guru**** 164746 points

Izumi-san,

As I remember , ICC can increase significantly between VCC = 4.5V to VCC = 5.5V, the point of increase varies device to device.

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Supply current on TRS202E