I have an application where I am using the LMH1218 Cable driver. I have two inputs connected to the device's 2:1 input Mux, but only 1 will be used at a time. The other will be effectively floating. Does the chip power down the unused inputs if it does not detect a signal on it? Or do I need to add external resistors to pull the inputs down. I would prefer not to add external parts due to the high-speed nature of the signals.
Thanks for the help.
Jesse C.
