Hi,
Please let me ask about required memory space described in Base Address Register 0 and Base Address Register 2. It's 64kB for Base Address Register 0 but Base Address Register 2 requires 8MB. I think that 8MB is too large so it should be 8kB. Is my understanding correct?
I found that some user 64kB and 8kB as following thread.
Best Regards,
Satoshi / Japan Disty
Hi Michael,
I think that 2^19 =524288 is 0.5MB, not 5MB. And also the value in datasheet is 8MB, not 5MB. Please confirm again.
Best Regards,
Satoshi
I was incorrect the data sheet is incorrect the correct table 23 is posted below.
Hi Michael,
I'm a little confused. Please let me know which is right answer for Base Address Register 2. The table 4-5 you attached is still incorrect, 12 bit should be 4096B (2^12=4096), not 1MB.
Best Regards,
Satoshi
We have looked at the datasheet again and here are the corrections
for Table 19
and the correct Table 23 is below
Hi,
Thank you for your support. I understand about Register 2. But please let me know why you don't refer the latest datasheet about Register 0? Do you mean that the Table 19 in latest datasheet is incorrect?
Best Regards,
Satoshi
