• State Resolved
  • Locked Locked
  • Replies 2 replies
  • Subscribers 32 subscribers
  • Views 289 views
  • Users 0 members are here
Support feedback
Options
Options
Similar topics

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

SN75174: How does a line driver create a -7 to +12 output differential from a 5V supply?

Derry
Prodigy 40 points
Part Number: SN75174

Hello,

The question is essentially in the title. Is the line driver acting as a current source and output voltage depends on the load being driven? How is the line driver able to provide more potential difference than the 5 V power supply?  Perhaps I'm misinterpreting the datasheet. 

Best,

Derry

  • 0
    TI__Guru 62920 points
    Hi Derry,

    The driver itself does not produce any voltages beyond the power rails (VCC and ground). The -7 V to +12 V working voltage range is specified for cases where there differences in ground reference potentials between different transceivers that share a common bus connection. In these cases, the common mode (rather than differential) component of the signaling could get biased to voltages outside the VCC range of a given transceiver. Let me know if this doesn't make sense.

    Max
  • 0 in reply to Miguel Robertson
    Prodigy 40 points

    Thanks that makes sense.