Using 3 coils: 1600 turns,2000 turns,5000 turnsUsing REFSEL1=0, REFSEL2=0, to supply 5V, reference voltage 2.5V modeGSEL1=1, GSEL1=0, mode 3, capacitance L > 50mL modeAccording to the calculation of Ip * Np = Is * Ns, under the current of 10.4 A, the corresponding currents of the three coils are:
Is=Ip*Np/Ns
- 1600 turns corresponding to Is=10.3*1/1600=6.47mA
-2000 turns corresponding to Is=10.3*1/2000=5.18mA
-5000 turns corresponds to Is=10.3*1/5000=2.06mA。
The current in the compensation coil is measured and the universal meter is strung into the coil L 1 and the sampling resistance R7. The measured results are in good agreement with the above calculation and work normally.
It is also normal to test the two-terminal voltage of the sampling resistance with a multimeter,
which is the product of the corresponding current and resistance value of each coil above.Theoretical Vout output, when the original edge current 0A changes to 10.3A, when the sampling resistance is 5.1 Ω, the corresponding output change of each coil is as follows:
1600 turns corresponding to Vout=4*Is*R7=4*6.47*0.001*5.1=0.132V
- 2000 turns corresponding to Vout=4*Is*R7=4*5.18*0.001*5.1=0.106V
- 5000 turns corresponding to Vout=4*Is*R7=4*2.06*0.001*5.1=0.042V
However, the actual test shows that the output of the three kinds of coils increases with the increase of the original edge current. When the original edge is 0 ≤ 10.3A, the total output variation is about 0.04V.
When the sampling resistance is changed to 10 Ω and the rest remain unchanged, the output change should be about doubled in theory, but the output of the three coils is the same, which is about 0.03V.
