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DS25BR440: Weird Output Behaviours when No Input Signal & Random Noisy Output when Input Signal at LVDS Common 1.2 V .

Part Number: DS25BR440

VDD pins 3, 8, 15, 25, 30 - Tied to power 3.3 V with decoupling capacitor 0.1 uF.

EQ0 - EQ3 pins 11, 12, 39, 40 - Ground.

PE0 - PE3 pins 18, 19, 20, 31 - Ground.

PWDN# pin 38 - Tied to power 3.3 V without any pull up.

PWDN0# - PWDN3# pins 32, 33, 34, 35 - Tied to power 3.3 V without any pull up.

LOS0# - LOS3# pins 13, 14, 36, 37 - Not connected as no output acknowledgement feature demanded in our case.

IN0 - IN4 - All LVDS inputs.

OUT0 - OUT4 - All LVDS outputs.

We observed that if all IN0 - IN4 LVDS inputs are all 0 V (no signals), OUT0 - OUT4 output channels will have behaviours as below:

a.) OUT0+ 1.3 V flat, OUT0- 1.1 V flat.

b.) OUT1+ and OUT1- both 1.2 V flat.

c.) OUT2+ 1.1 V flat, OUT2- 1.3 V flat (polarity inversion compared to item a.)).

d.) OUT3+ 1.5 V flat, OUT3- 0.9 V flat (larger peak-peak compared to item a.)).

Why the 4 output channels behaviour will be different among each other?

We try to setup the above 4 conditions to be connected to IN0 - IN4 this time, and the observations as below:

a.) If any IN+ and IN- have both 1.2 V flat (common), OUT+ and OUT- on that particular channel will surely have signals flipping.

b.) If any IN+ and IN- in LVDS differential form, OUT+ and OUT- on that particular channel will follow what the input be.

c.) Channel 2 will always have polarity inversion.

d.) All channels output peak-peak value will increase. OUT+ 1.5 V, OUT- 0.9 V.

Why common 1.2 V signals will cause signal flipping? Why channel 2 always have polarity inversion?

  • Hi,

    The input threshold is typically ~ 0V differential.  So if the input is allowed to float the output state can not be predicted.  When there is no differential input on a channel, using PWDN to reduce power will mute the output.

    Alternately, biasing the input differential pins to a slightly positive or slightly negative bias (~25mV) can help to stabilize the device output when no input signal is present.

    Regards,

    Lee