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ONET2804TLP: Transimpedance gain vs input current

Part Number: ONET2804TLP

Dear TI Experts,

I am trying to understand how figures 1 and 5 in the ONET2804TLP datasheet relate to each other. I would expect that the transimpedance of the amplifier would be defined as the gradient of the I-V curve in figure 5. However figure 1 shows that it is still non-zero for input currents where figure 5 is flat. How, then, is the transimpedance defined in the case of figure 1? And what is the reason that the transimpedance is not flat for input currents up to ~50uA (then dropping rapidly to zero)?

Thanks for you help with this.

Kind regards,

Joel

  • Hello Joel,

    This is because there are different stages of the device that determine the differential output voltage. The transimpedance that the datasheet is referring to in figure 1 is the feedback resistance across the TIA stage shown in the block diagram below: The differential output voltage in figure 5 is the final output after the signal has gone through the gain stage and output buffer. Hope this clarifies things!

    Best,

    Hasan Babiker