• State TI Thinks Resolved
  • Locked Locked
  • Replies 1 reply
  • Answers 1 answer
  • Subscribers 33 subscribers
  • Views 429 views
  • Users 0 members are here
Support feedback
Options
Options
Related

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

WEBENCH® Tools/SN65HVD1781A-Q1: SN65HVD1781A-Q1

Roi Kobo
Intellectual 680 points
Part Number: SN65HVD1781A-Q1

Tool/software: WEBENCH® Design Tools

Hello

I connect the SN65HVD1781A-Q1 part to my MCU. The VDDIO of the MCU is 3.3V and the other side connect to my connector.

Please let me know If my connection is good ( A,B = 5V logic level from my connector and the Receive data output, R=3.3V logic level to MCU)

  • 0
    TI__Guru 62920 points

    Hello,

    It will depend on the specifications of the MCU's IO pins.  For the outputs, they would need to be able to drive above 2 V for high levels and below 0.8 V for low levels.  If that is the case, they could interface to the logic inputs of the transceiver properly.  For the inputs, they would need to be tolerant to 5-V inputs and have "VIL" and "VIH" threshold levels that are compatible with the "VOL" and "VOH" levels of the transceiver output.  If the MCU is not 5-V tolerant, you could use a level translating device or simply block the higher voltage from the transceiver by placing a diode in series with the output (with cathode facing the "R" output).  This will effectively turn the R output into an open-drain style driver, and a pull-up resistance to 3.3 V could be placed at the MCU input in order to properly pull to high logic levels.

    Please let us know if this is unclear or if you have any further questions.

    Regards,
    Max