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AM26LV31E: Enable input resistance

shlomi ben shushan
Prodigy 100 points
Part Number: AM26LV31E

Hello.

In AM26LV31E datasheet mentioned that the enable maximum input current is 1[uA].

In the equivalent circuit shwon that the enable has input resistance but with no value.

Does it's meen that if i want to use 3.5V as input i need a minimum of 3.5 Mega ohm resistor ????

Thank you.

  • 0
    TI__Guru 62920 points

    Hi Shlomi,

    Typically when applying a voltage to the pin it would be through a resistance much smaller than the input resistance of the device. For example, an MCU's GPIO might typically be in a range of 20 to 50 Ohms. Because of this, the leakage current of the pin would be relatively insignificant and not cause a change in the voltage. Even if you were to bias the pin using a pull-up or pull-down resistance, a typical maximum value would be 10 kOhm. If you had, for example, a 10 kOhm pullup to 3.3 V, then the 1 uA of leakage current would result in a voltage at the pin of 3.3 V - (10 kOhm) *(1 uA) = 3.29 V.

    The leakage current is only significant enough to consider if you were to bias the pin using a very high resistance.

    Regards,

    Max