This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

About CAN Transceiver EN state on the sleep mode

Hi all,

I could find this picture on the CAN Transceiver datasheet, and I wonder the state of EN pin on the sleep mode.

I knew that the only state on EN is High or Low, I could know that EN of the CAN Transceiver is LOW at first and it changes to HIGH when the mode is changed to the Normal.

I could see the state of EN is x, I do not understand the x meaning.

It's written that "the enable pin can be in a logical high or low state on the sleep mode" I also do not understand what this meaning.

Could you please explain me detail for this?

  • Garam,

    "X" simply means that the state of the pin is not relevant.  It could be either high or low without any difference in effect in this mode.

    Regards,
    Max

  • Thank you Max,

    I could see the "CAN:weak ground" on the Standby mode, go to sleep mode, and sleep mode, could you please explain what the weak ground means?

    I could find the INH:floating on the sleep mode on the picture.

    I know that the INH has two state (high, high Impedance), when it is high, output is Vsup-Vfet_diode, when it is high impedance, output is floating.

    Can I think high impedance is INH Low?

    What is the meaning of floating when INH is high impedance?

    Thank you

    INH floating

  • Hello,

    "Weak ground" means that CANH and CANL are biased to ground via the input resistances of the receiver; you can reference Figure 20 in the datasheet for an equivalent schematic and some more information.

    "High impedance" on INH means that it acts as an open circuit - i.e., it sources/sinks minimal current.  If you wanted to ensure that this "floating" output results in a low state, you could use a pull-down resistor to connect INH to ground.  A value like 100 kOhm is common and would allow the voltage to be near 0 V when INH is high impedance without sinking much current when INH is pulled up to VSUP.

    Regards,
    Max