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Original question:

SN6505B: Application Question

SN6505B: SN6505B Consultation on usage issues

wang lei
Prodigy 100 points
Part Number: SN6505B


Tool/software:

Hello experts,

    I prepare to use SN6505 to design a push-pull circuit. The transform we used is Bourns HCTSM80308BAL, Turns Ratio 3:8.

I have some questions shown as below:

1、How to calculate the push-pull circuit output voltage?

2、How to calculate the push-pull circuit output current?

Thank you in advance.

  • 0
    TI__Mastermind 31865 points

    Hello Weng, 

    The equation for a transformer is P_primary = P_secondary or I_p*V_p=I_s*V_s. This means power on side 1 (primary) of the transformer will be equal to the power on side 2 (secondary) of the transformer.

    For example, let's say you have a Vin of 5V and the SN6505B datasheet shows a maximum current of 1A. Then the total power at side 1 of the transformer would be P1=IV or 5W. 

    The transformer you selected has a 3:8 turn ratio (Np:Ns).

    1. Using the above equation, we solve for output voltage (Vs). Vs=(Ns*Vp)/Np and comes out to Vs = 13.3V.
    2. Since power is conserved, the Ps = 5W. Therefore, output current is Is = 5W/13.3 = 0.375A. 

    Let me know if you have further questions. 

    Best,
    Andrew