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SN74AUP1T97: Consequences to tying A, B, and C for Logic Buffer

Part Number: SN74AUP1T97

Hello, I plan to use the SN74AUP1T97 as a level shifter to bring up a peripheral's logic from 1.8 to 3.3 volts to be read by my microcontroller, however I noticed that the peripheral manufacturer's design which referenced your part is using a PIN set up that is not shown in your datasheet. In their design, they have the A B and C terminals tied together. After working through this setup, I concluded that its output behavior is the same as a non-inverting buffer, which is one of the designs included in your datasheet. I prefer your datasheet's design to the one implemented by the peripheral designer because their design would require more gates to switch their states in order to accomplish the same task. I was hoping to ask if there is any reason you can think of why they would have used that alternate configuration/ if that configuration could lead to errant logic? My intuition is that their design could lead to garbage bits if there is logic changing fast enough that there could be gate propagation issues. Thank you very much in advance -Joe

  • Hey Joe,

    I'm not entirely sure why they would go with that configuration over the example in the data sheet. However, I dont really see a down side to their configuration with all 3 inputs shorted together. There is one extra inverter stage in the C channel, but the delay added would be negligible (likely in the ps range). Even looking through the logic with the C input lagging behind, it looks like the output state would remain the same. The example configuration eliminates that possibility altogether (keeping that input static) and would also reduce the added input capacitance the peripheral would have to drive.