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CD4056B: Component information requirement

Part Number: CD4056B

Hi,

In our internal part number apply SOP, information below are needed

(EE) * Component Version:  
(EE) * MSDC Level:  
(EE) * Part Grade  (Car, Military, NEBS Level1, NEBS Level2, NEBS Level3, Normal ) :  
(EE)_* Plastic Material:  
* Junction Temperature (Tj) (°C):  
* Theta-JA (°C/W):  

Please support

Thanks  

  • Hello,

    This forum is for technical inquiries - ie system design assistance.

    For this type of request, I would recommend to submit to the customer support center here: https://ticsc.service-now.com/csm 

  • Hi Emrys,

    Thanks for your advise. I open "CS1278895 " in your support center.  Max Xu in Customer Support Center had provided me the  "Junction Temperature (Tj) (°C):  -55- 125℃".

    Max said that else information i could go back to E2E to ask.

    Could you help to give comments? 

  • Hi Rendol,
    I will reach out to Max and his manager to find out why they couldn't provide you with the information requested.

  • Hi Rendol,

    I believe this is getting sorted out so the CSC will help you with most of your questions. Please let me know if you need further assistance.


    FYI - the max junction temperature for this device is 150 ºC, which is listed in our logic FAQ section here: [FAQ] What is the maximum junction temperature (TJMAX) for a device?

    Also, for the R_θJA specification, this device doesn't list an R_θJA, but instead provides the maximum power dissipation:

    The purpose of R_θJA is to calculate temperature increase from power dissipation to ensure that the device can function under a specific set of conditions. In older devices like this one, a flat value was provided, so if the device is being operated with 500mW or less of power dissipation, then it can operate from -55C to 100C.

    We can use this to calculate an R_θJA if you just really need one, but for normal operation, the highlighted values are what should be used.

    For the calculation:

    R_θJA = ( TJ(max) - TA(max) ) / P_D = (150 - 100) / 0.5 = 100 ºC/W