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TXS0102 Pull-up Resistor on OE Pin

J Evans
Prodigy 200 points
Other Parts Discussed in Thread: TXS0102, TXB0102

Hi There,

I will be using the TXS0102 device for voltage translation between 1.8 VDC (VCCA pin) and 5 VDC (VCCB pin) UART signals.

My question relates to the OE pin. For the TXB0102 device, that data sheet mentions that the OE pin is just connected to VCCA internally. For the TXS0102 device, the data sheet only talks about connecting the OE pin to ground when the device is not needed.

Assuming that the OE pin for the TXS0102 device needs to be connected to the VCCA pin, should I put a 10k resistor between OE and VCCA?

I searched online for an example and this design did that, but I wanted to be certain this resistor is needed.

http://omer.me/uploads/ponte-schematic-revc-300x197.png

Oh, and I understand that I could just use the TXB0102 device, but I already have the symbol/layout for the TXS0102.

Many thanks,

James

  • 0
    TI__Expert 4705 points

    Hi, James

    For the TXB0102 and TXS0102, they are same, not sure where did you get the information for the OE internally connect to VCCA for TXB0102.

    For OE, it can be floating, we have same recommendation that put to GND through a resistor if you want keep the high-z state when power up.

    If not, it can be connected to VCCA directly either through a resistor or not.

    For your design, if it is for UART, you can use either of them. and also for some package , TXS0102 and TXB0102 are pin-pin compatible, if you want to change, you can check the datasheet. if not, you can keep the TXS0102.

     

    BR
    Junjie

  • 0 in reply to Junjie Mai
    Prodigy 200 points

    Hi Junjie,

    Thanks for the clarification. I will use the TXS0102 device and connect OE directly to VCCA.

    Table 1 in the TXB0102 datasheet mentioned that OE is "referenced to VCCA" which I misunderstood it to be internally connected or referenced to VCCA, but instead, as you pointed out, OE either gets pulled low to GND or gets pulled high using VCCA (hence the reason it references VCCA voltage levels).

    I appreciate your help and time.

    Thanks,

    James