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Hi,
If we have an IC with CMOS output, and cut of its power supply by means such as a switch disconnecting its VCC, then what happens at output pins? Would parasitic cap's voltage keep one of the MOSFET on?
Calino
Daniel,
What about the cases for:
i: 1.8V/3.3V TI processor GPIO, like for MSP430, Keystone, C2000, etc.?
ii: TI signal muxes.
Calino
Hi Carlino,
Q1: The 10Mohm resistances that is generally seen on MOSFET devices is because their gate must have a finite resistance. I used 10 Mohms because generally that is the order of magnitude that MOSFETS will have as their resistance however that is not the rule. You can assume non ideal devices have a resistance, just not necessarily 10Mohm.
Q2: Below I have an attached a diagram that shows the ESD diodes and their interactions with parasitic capacitances and the paths through the diodes is where the capacitors will drain. I am not allowed to comment on any of the devices that you have listed since you should ask about those in their respective forum.
i) Microcontrollers forum
ii) ON Semi's own forums
iii) The Switch/Mux forum
iv) The amplifiers forum
I do believe however that the below diagram will be the case, i do not guarantee this however for the parts you listed.
Thanks,
Daniel
Hi Calino,
Q1: The path is highlighted below. The Vcc in this circuit is 0V in this case because the Vcc has been switched off by whatever you are doing.
Q2: I suggest looking at HSPICE and LTSPICE. If you are at a university sometimes they have a commercial license you can get by talking to some of the professors.
Q3: From what I have heard most people use HSPICE however that doesn't happen in my area.