- Ask a related questionWhat is a related question?A related question is a question created from another question. When the related question is created, it will be automatically linked to the original question.
Hi,
In SLVA675B, It says
- Remember that the LSF device acts as a passive switch when the input signal is below Vref_A – 0.5 V
- When the input voltage exceeds Vref_A – 0.5 V, the FET turns off and the pullup resistor on the B-side determines the output voltage. Therefore, the designer needs to pull up the B-side to 3.3 V. •
- The FET begins to turn off when the input voltage exceeds Vref_A – 0.5 V. As discussed earlier, the FET should be on during the input low pulse and off during the input high pulse. Therefore, set Vref_A to 1.8 V.
As above assumption, when down from B to A, the A output should be Vref_A – 0.5V. But in document it says: When translating down from B to A, this allows the A-side voltage to equal Vref_A + VTH – VTH = Vref_A without any pullups.
How to understand this?
Thanks a lot!
