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Mux/Demux and impedance match

Anonymous
Anonymous
Other Parts Discussed in Thread: SN74CBT3257, SN74CBT16292

Hi All,

 

I would like to ask some questions on logic devices.

 

 

 

 

I.

The first question is that does the output voltage level equal input level? Fig. 1 is from the PARAMETER MEASUREMENT INFORMATION part of

1.      SN74CBT3257 Mux / Demux

2.      SN74CBT16292 Mux / Demux

and these contents are the same in the documents of these two devices.

 

From the left of Fig. 1, if seems that input’s 1.5V, which is half in the rise between low and high, is the same in output. So does this suggest that these logic devices keep the output voltage level the same as input voltage level?

 

II.

The second question is on the right of Fig. 1, in which I don’t understand what the curved shape mean. In the dashed box on the left, the transition is straight; why on the right it is a smooth curve?

 

II.

The third question is on these logic devices’ effect on impedance matching. In this attached Fig. 2, data lines coming out from DM6437 (these pins are multiplexed with COUTxx pins so the net is labeled as COUTxx) are first connected to Mux/Demux before connecting with memory devices (NOR flash and SRAM). There are termination resistors of 22 Ohm at the DSP pins to matching with the impedance of tracks.

 

 

 

 

But does the impedance matching take the intermediate Mux/Demux into account? The formula for impedance-matching resistor value is:

Rdriver + Rresistor = Zo

So what is the role of these Mux/Demux here? The schematics is from EVM6437 by Spectrum Digital so I believe the matching is good, but if I am removing these intermediate mux/demux, do I need to change the value of those impedance-matching resistors?

 

  

 

 

Thanks,

Zheng

  • I.

    The first question is that does the output voltage level equal input level? Fig. 1 is from the PARAMETER MEASUREMENT INFORMATION part of

    1.      SN74CBT3257 Mux / Demux

    2.      SN74CBT16292 Mux / Demux

    Yes  the output will equal the input until it reaches Vcc-1V. Then it will be clamped. So if you have a 0v to 5V siganal going in and the Vcc is 5V then the signal coming out will be 0V to 4V. If you have a 0V to 3V signal going in then the output signal will be 0V to 3V.

     

    II.

    The second question is on the right of Fig. 1, in which I don’t understand what the curved shape mean. In the dashed box on the left, the transition is straight; why on the right it is a smooth curve? 

     The curved shape is used any time you go into a high impedance state. It shows the output floats.

     

    II.

    The third question is on these logic devices’ effect on impedance matching. In this attached Fig. 2, data lines coming out from DM6437 (these pins are multiplexed with COUTxx pins so the net is labeled as COUTxx) are first connected to Mux/Demux before connecting with memory devices (NOR flash and SRAM). There are termination resistors of 22 Ohm at the DSP pins to matching with the impedance of tracks.

     These switches only add a few ohms series resistance so the terminations should not need to be changed.

  • Anonymous
    0 Anonymous in reply to Chris Cockrill

    Dear Chris,

    Thanks very much for your timely answer. They resolved all my questions on this.

    Zheng