• State TI Thinks Resolved
  • Locked Locked
  • Replies 3 replies
  • Answers 2 answers
  • Subscribers 20 subscribers
  • Views 331 views
  • Users 0 members are here
Support feedback
Options
Options
Related

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

TXS0102: TXS0102 Δt/Δv question

Mason Liu
Expert 4035 points
Part Number: TXS0102

Hi,

In TXS0108 spec, it says:

It says to be 10ns/V as the “max” value for rise rate. any rise rate less than 10ns/V should be acceptable, which will lead to for example 8ns/V or 9ns/V, but 9nv/V's rate is actually higher than 10ns/V. so i'm a little confused here, could you give me some suggestions?

Thanks.

BR

Mason

  • 0
    Guru 316510 points

    "Max" applies to the numeric value, so 10 is higher than 9.

    Please note that the I/O limits apply only to push/pull driving; there are no limits for open-drain signals. (The TXS device itself does not actually differentiate them; the Δt/Δv limit is necessary only to guarantee the switching characteristics for push/pull driving.)

  • 0 in reply to Clemens Ladisch
    TI__Expert 4035 points

    Hi Clemens,

    Thanks for the explanation, yes I  agree with you that the "Max" applies to the numeric value, 10 is higher than 9, but if considering the "ns/V", 9ns/V's ramp up rate is higher than 10ns/V. in that case, seems like we limit the minimum rate, not the maximum rate. correct me If i'm wrong.

    Thanks.

    BR

    Mason

  • 0 in reply to Mason Liu
    TI__Mastermind 45725 points

    Hey Mason,

    Not quite sure what you are getting at, but hopefully the clarification below will help:

    The rising/falling edge should not exceed 10 ns/V. This is the maximum limit. The minimum would theoretically be 0ns/V, an instantaneous transition as it takes 0 ns to rise or fall 1 V. Exceeding the maximum Δt/Δv of 10 ns/V would mean that your rising or falling edge takes longer than 10 ns to rise or fall 1 V (e.g. 11ns/V).