This thread has been locked.
If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.
Hello,
The resistances R1 and R2 are typically 7K-ohm and 5K-ohm respectively. These values are selected such that two combinations of the BRIDGE_EN and HILO bits yield 7/12th and 5/12th of VREFHI as the reference voltage converted (with VREFLO = 0V). The {BRIDGE_EN = 0, HILO = 0} combination gives a conversion result of 0x952.
This is a result of the reference voltage being VREFHI * 7/12.
Similarly, you will get a reference voltage of VREFHI * 5/12 for the {BRIDGE_EN = 0, HILO = 1} combination.
I have verified this on a USB stick here.
Please confirm that there is no issue with the documentation.
Regards,
Sunil
BRIDGE_EN = 0, HILO = 0 => 2386 ( ~ 7/12)
BRIDGE_EN = 0, HILO = 1 => 1704 ( ~ 5/12)
BRIDGE_EN = 1, HILO = 0 => 0
BRIDGE_EN = 1, HILO = 1 => 4094
Hi Bastian,
Since R1 is 7KOhm and R2 is 5KOhm, BRIDGE_EN = 0, HILO = 0, and AD_REFLO is 0V then I would interpret row 1 of the following table
to result in 7K*AD_REFHI / (7K+5K) or 7/12*AD_REFHI rather than 5/12*AD_REFHI. You don't agree?
Bastian,
You are correct. We need to be more clear on this point. We have this as a ticket to fix this in future TRM releases. Sorry for your trouble!