Other Parts Discussed in Thread: SYSCONFIG, MSPM0G3507
I have set 2 gpio's as input.(PA18,PB21) and set them to interrupt on falling edge. The GPIO_input_capture example provided shows how to use a single interrupt. I would like to do the same thing with 2 interrupts. Could an explanation also be given to what exactly is happening in the example provided and what else should I add to the below code for the 2nd interrupt(couldn't find any related interrupt docs in trm). What I am trying is to turn on the led by first interrupt and off by the second interrupt. And in the example it seems that the input pin(where the interrupt occurs) is internally pulled up. I can't understand where in the code or sysconfig a internal pull up is given?
BELOW IS THE EXAMPLE PROVIDED:
#include "ti_msp_dl_config.h"
extern volatile uint32_t interruptVectors[];
int main(void)
{
SYSCFG_DL_init();
/*
* Turn OFF LED if SW is open, ON if SW is closed.
* LED starts OFF by default.
*/
NVIC_EnableIRQ(GPIO_SWITCHES_INT_IRQN);
while (1) {
__WFI();
}
}
void GROUP1_IRQHandler(void)
{ switch (DL_Interrupt_getPendingGroup(DL_INTERRUPT_GROUP_1))
{ case GPIO_SWITCHES_INT_IIDX:
if (DL_GPIO_readPins(GPIO_SWITCHES_PORT, GPIO_SWITCHES_USER_SWITCH_1_PIN)) /* If SW is high, turn the LED off */
{
DL_GPIO_setPins(GPIO_LEDS_PORT, GPIO_LEDS_USER_LED_1_PIN);
}
else /* Otherwise, turn the LED on */
{
DL_GPIO_clearPins(GPIO_LEDS_PORT, GPIO_LEDS_USER_LED_1_PIN);
}
break;
}
}
