MSPM0L1228: What are the last 8 bytes in code memory region used for?

Sho Takayama

Part Number: MSPM0L1228

Tool/software:

Hi,

I have two questions about flash bank memory size in MSPM0L-1228.

As show in the image below, the size of Code (Flash Bank 0/1) memory region is from 0x0000.0000 to 0x0001.FFF8 ( or 0x0002.0000 to 0x0003.FFF8 )

- What are the last 8 bytes used for? ( 0x0001.FFF8 to 0x0001.FFFF, or 0x0003.FFF8 to 0x0003.FFFF )

- I think it is not a good idea to use these bytes to store user data. But, what happens if I write data to these bytes?

Thanks and Best Regards!

8 months ago

0 Helic Chi 8 months ago

TI__Genius 12822 points

Hi, Sho san

It's better to leave last 8 bytes alone and do not do any operation at them.

Sho Takayama said:
But, what happens if I write data to these bytes?

You can have a try, try some Rd/Wr operation to them.

But I don't recommend you to do such thing in final product. This will cause unpredictable results.

Regards,

Helic

0 Bruce McKenney 8 months ago

Guru 96315 points

I think it has to do with Prefetch, which might reach out beyond the memory boundary and generate (bogus) memory exceptions. I (vaguely) recall that some number of Arm-based MCUs (not just TI) exhibit this artifact.

Arm-based microcontrollers

Arm-based microcontrollers forum

MSPM0L1228: What are the last 8 bytes in code memory region used for?