MSPM0L2228: Prevent Wake-up by the RTCRDY Interrupt

Part Number: MSPM0L2228

Tool/software:

Hi,

Could you please tell me how to prevent wake-up by RTCRDY interrupt while in standby mode?
To achieve this, I wrote 0xA9000100h to the RTC.CLKCFG register and enabled the RTCRDY interrupt as shown below:

1. Write 0xA9000100h to the RTC.CLKCFG register
using the TI sample (rtc_a_tamper_timestamp_event) and Add RTC_A->GPRCM.CLKCFG = 0xA9000100U; to line 44.

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#include "ti/devices/msp/peripherals/hw_rtc.h"
#include "ti_msp_dl_config.h"

volatile bool gCheckTSEVT = false;
volatile uint32_t counter = 0;
volatile uint8_t gBlink;

int main(void)
{
    /* Initialization */
    SYSCFG_DL_init();
    
    RTC_A->GPRCM.CLKCFG = 0xA9000100U;

    /* Enable the RTC interrupt at NVIC */
    NVIC_EnableIRQ(RTC_A_INT_IRQn);

    /* Start RTC clock */
    DL_RTC_A_enableClockControl(RTC_A);

    while (1) {
        __WFI();

        /* Wait in a while() loop until the time stamp interrupt triggers - Trigger a tamper event externally */
        while (gCheckTSEVT == false)
            ;

        /* Blink LED a number of times equal to amount of time stamp events detected */
        if (DL_RTC_A_getTimeStampEventCause(
                RTC_A, DL_RTC_A_TIME_STAMP_EVENT_CAUSE_TIO_0) ==
            DL_RTC_A_TIME_STAMP_EVENT_CAUSE_TIO_0) {
            for (gBlink = 0; gBlink < (2 * counter); gBlink++) {
                DL_GPIO_togglePins(GPIO_LEDS_PORT, GPIO_LEDS_USER_LED_1_PIN);
                delay_cycles(16000000);
            }
        }
    }
}

void LFSS_IRQHandler()
{
    switch (DL_RTC_A_getPendingInterrupt(RTC_A)) {
        case DL_RTC_A_IIDX_TSEVT:
            counter++;
            gCheckTSEVT = true;
        default:
            break;
    }
}

2. Enable the RTCRDY interrupt.



However, the Default_Handler was called when the registers were set.

Are there any correct settings or other methods?

Regards,
Sho Takayama