MSPM0C1104: How to change a uart tx pin to be an output gpio then switch back to uart tx

bill.liao

Part Number: MSPM0C1104

Tool/software:

Hi, experts:

As the title we need to change a tx pin(PA23) to be an output gpio for a while in certain case, pull down the gpio for 1ms, then switch back to uart tx, below is the code and seems working well, but still I want a confirmation from you in case anything is missing, thanks.

Bill

#define GPIO_UART_0_IOMUX_TX                                     (IOMUX_PINCM24)
#define GPIO_GRP_0_PORT                                                  (GPIOA)
#define GPIO_UART_0_TX_PIN                                        DL_GPIO_PIN_23
#define GPIO_UART_0_IOMUX_TX_FUNC                      IOMUX_PINCM24_PF_UART0_TX


DL_GPIO_initPeripheralOutputFunction(
              GPIO_UART_0_IOMUX_TX, IOMUX_PINCM24_PF_GPIOA_DIO23);
DL_GPIO_initDigitalOutput(GPIO_UART_0_IOMUX_TX);
DL_GPIO_clearPins(GPIO_GRP_0_PORT, GPIO_UART_0_TX_PIN);
DL_GPIO_enableOutput(GPIO_GRP_0_PORT, GPIO_UART_0_TX_PIN);

delay_cycles(24000);
DL_GPIO_setPins(GPIO_GRP_0_PORT, GPIO_UART_0_TX_PIN);

DL_GPIO_initPeripheralOutputFunction(
GPIO_UART_0_IOMUX_TX, GPIO_UART_0_IOMUX_TX_FUNC);

The macro in the code is from ti_msp_dl_config.h

10 months ago

0 bill.liao 10 months ago

Intellectual 325 points

ps: the code above is called in a wake up from standby0

0 Zoey Wei 10 months ago

TI__Genius 12851 points

Hi Bill,

If you want to only using GPIO to pull down the line, there will be more convenient way to realize this, please refer to below code:

 DL_UART_enableLINSendBreak(UART_0_INST);
delay_cycles(16000);
DL_UART_disableLINSendBreak(UART_0_INST);

And if you still want to change TX to GPIO function, your code looks good.

Regards,

Zoey

0 bill.liao 10 months ago in reply to Zoey Wei

Intellectual 325 points

Thanks Zoey, it works well in your way.

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MSPM0C1104: How to change a uart tx pin to be an output gpio then switch back to uart tx