Hi,
we are using a RM48L952 with 64k of EEPROM-Emulation-Flash and we are using 4 virtual sectors. Now we wonder how many kb of data we will be able to save. We came to two possibilities but are not sure which one is really implemented:
1)(more space, less erase cycles)
The FEE-driver uses (No_of_virtual_sectors - 1) sectors to save the data and one VSector for the copy process. In our excample we would have 3*(64/4)KB =48KB of space to save our data.
2)(less space, more erase cycles)
The FEE-driver uses only one virtual sector to save the data and all other sectors for the copy process. (VS1 full -> write to VS2, VS2 full -> write to VS3 and so on). In this case we would have only 64/4KB = 16KB of space to save data.
Can somebody tell us which way is the correct/implemented one?
Regards,
Frank