interrupts

Dear all

I'm trying to use interrupt on GPIO Pin, in this case PE5 pin. I fixed the interrupt on falling edge.

Loop enter into the interrapt routine but continue to eneter in it forever.

Following my code:

void IntGPIOe(void){
   
   while (1){
        
       value= (GPIOPinRead(GPIO_PORTE_BASE, GPIO_PIN_5));
       if (value!= 0) break;
 }
 
    
     GPIOPinWrite(GPIO_PORTQ_BASE, GPIO_PIN_7, 0x80);

     SysCtlDelay(1000000);

    GPIOPinWrite(GPIO_PORTQ_BASE, GPIO_PIN_7, 0x00);
   
   SysCtlDelay(1000000);
   
}



int main(void) {
 
    // Run from the PLL at 120 MHz.
    ui32SysClock = SysCtlClockFreqSet((SYSCTL_XTAL_25MHZ |
                                       SYSCTL_OSC_MAIN |
                                       SYSCTL_USE_PLL |
                                       SYSCTL_CFG_VCO_480), 120000000);

        
      SysCtlPeripheralEnable(SYSCTL_PERIPH_GPIOQ);               
     GPIOPinTypeGPIOOutput(GPIO_PORTQ_BASE, GPIO_PIN_7);  // PQ7 as outputs
     
    SysCtlPeripheralEnable(SYSCTL_PERIPH_GPIOE);
    GPIOPinTypeGPIOInput(GPIO_PORTE_BASE, GPIO_PIN_5);            // PE5 as input
    GPIOIntTypeSet(GPIO_PORTE_BASE, GPIO_PIN_5, GPIO_FALLING_EDGE);  // interrupt on Falling edge
    GPIOIntEnable(GPIO_PORTE_BASE, GPIO_INT_PIN_5);
    IntEnable(INT_GPIOE);

    // Loop forever.
    //
    while(1) ;
  
}

Code enter in the interrupt service routine  when I press the button, then continue to enter in it.

Any Idea?

Thanks for all

Marco