Hello.
I have question at efuse error.
ESM error flag Group 1 Channel 40 is not set, I don't know why in this case.
Below code is "efcStuckZeroTest" in "sys.selftest.c".
In this function substitute "EFC_INSTRUCTION_INFO_EN" for "uint32 error_checks".
After, execute "efcREG->BOUNDARY = OUTPUT_ENABLE; " .
I think that these operations will set a single bit error to ESM Group 1 Channel 40.
*/
/* SourceId : SELFTEST_SourceId_012 */
/* DesignId : SELFTEST_DesignId_014 */
/* Requirements : HL_SR402 */
boolean efcStuckZeroTest(void)
{
/* USER CODE BEGIN (29) */
/* USER CODE END */
uint32 ESM_ESTATUS4, ESM_ESTATUS1;
boolean result = FALSE;
uint32 error_checks = EFC_INSTRUCTION_INFO_EN |
EFC_INSTRUCTION_ERROR_EN |
EFC_AUTOLOAD_ERROR_EN |
EFC_SELF_TEST_ERROR_EN ;
/* configure the output enable for auto load error , instruction info,
instruction error, and self test error using boundary register
and drive values one across all the errors */
efcREG->BOUNDARY = ((uint32)OUTPUT_ENABLE | error_checks);
/* Read from the pin register. This register holds the current values
of above errors. This value should be 0x5c00.If not at least one of
the above errors is stuck at 0. */
if ((efcREG->PINS & 0x5C00U) == 0x5C00U)
{
ESM_ESTATUS4 = esmREG->SR4[0U];
ESM_ESTATUS1 = esmREG->SR1[2U];
/* check if the ESM group1 channel 41 is set and group3 channel 1 is set */
if (((ESM_ESTATUS4 & 0x200U) == 0x200U) && ((ESM_ESTATUS1 & 0x2U) == 0x2U))
{
/* stuck-at-zero test passed */
result = TRUE;
}
}
/* put the pins back low */
efcREG->BOUNDARY = OUTPUT_ENABLE;
/* clear group1 flag */
esmREG->SR4[0U] = 0x200U;
/* clear group3 flag */
esmREG->SR1[2U] = 0x2U;
/* The nERROR pin will become inactive once the LTC counter expires */
esmREG->EKR = 0x5U;
return result;
}
Best Regards
