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Compiler/LAUNCHXL-F28069M: 16 Bits per Byte or 8 Bits per Byte

user4957458
Expert 1065 points
Part Number: LAUNCHXL-F28069M

Tool/software: TI C/C++ Compiler

Hi All

 A line of a ".cmd" file of a project is 

  RAML4       : origin = 0x00A000, length = 0x004000     /* on-chip RAM block L4 */

This block of RAM is 0x004000 x 16 bits or 0x004000 x 8 bits?

Thanks

Luis Gonçalves

  • 0
    TI__Mastermind 27200 points
    Hi Luis,

    On C28x, the minimum addressable memory width is 16 bits. When you declare a "byte" or "char" in C, you are creating 16 bit variables on this machine.

    The linker command file is specifying 16 bit memory size, so in this case: 0x004000 x 16 bits.

    Regards,

    Richard