Instruction Set Help - Interrupt Vectors

william hutt

New Question:

0FFF4 - Watchdog-timer interrupt vector

0FFF4 MOV.B @R6, 0FFFF(R7) Where R6's address is 5644 and contains 33 in that address.

R7's address is 5732

If I understand this correctly the instruction will take the contents of address 5644 and store it in the address 0FFFF +R7

Expanding this out: 0FFFF + 5732 which makes the new address 5731? Is that correct?

Will 33 be stored in address 5731?

over 17 years ago

0 Antonio Espirito-Santo over 17 years ago

Expert 2855 points

Yes, it is correct.

But, remember, If the destination address is located in flash the moving operation will take no effect.

AES

0 william hutt over 17 years ago in reply to Antonio Espirito-Santo

Prodigy 110 points

New Question

&FFEE - ADC12 Interrupt Vector

FFEE MOV.B 0FFEF,R7

I believe this will put 00EF in Register R7, Is that correct?

0 BrandonAzbell over 17 years ago in reply to Antonio Espirito-Santo

TI__Guru 64820 points

What is the 16-bit value found at address 0xFFEE?

The values in the interrupt vector addresses, of which 0xFFEE is, are actually addresses, not instructions. When the MSP430 takes in interrupt, depending on which interrupt is given priority, that particular interrupt vector is loaded into the PC.

0 william hutt over 17 years ago in reply to BrandonAzbell

Prodigy 110 points

Since my last post I figured out that the NoICE disassembler converts the instruction into an address where the interrupt routine resides.

Ex:ample Line from Disassembler:

FFEE 5845FFFF Mov.B 0FFEF, R7

Tthe interrupt routine is located at address 4558

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Instruction Set Help - Interrupt Vectors