Error while declaring array and for loop in Code Composer Studio 4

venka tesh said:

char a[] = "string to be entered" ;  <--error is : expected a "}"

You declared a as a character array, yet initialized it with a string.

Perhaps you meant:

char* a = "string to be entered";

or...

char a[] = { 's', 't', 'r', 'i', 'n', 'g', ' ', 't', 'o', ' ', 'b', 'e', ' ', 'e', 'n', 't', 'e', 'r', 'e', 'd', '\0' };

venka tesh said:

for(int i = 0;i<sizeof(a);i++)  <-- error is: expected a declaration. I've declared i outside and initialized here.But still                                                            the error persists

How is the compiler supposed to know what the size of "a" is? Since "a" is a technically pointer to some piece of data, you could change the value of "a" and the size could be different.

I think you'd be better off with something like:

for(int i = 0;a[i] != '\0';i++)

Hello Venka,

If memory serves, expression-1 as a declaration was not supported until C99.  Our compilers are C89 with support for GCC extensions.  Declare i outside and initialize inside.

int i;

for(i=0; ...

However, looking at what the code is doing, it might be easier to just use something like

while(a[i] != "\0")

instead of a for () statement.