Hello Dear,
We need a clock interrupt of 1sec. We have out the timer configuration as follows on MSP430F5137
1. Clock source = ACLK (32K)
2. Clock Div = 3. (Div by 8). TA1CTL |= ID_3;
3. Count = 4K
This will suffice. But when I am trying to use TAIDEX Bits along with ID bits to get bigger clock divide and smaller count nuber number, it is failing to give interrupt.
If we use this setting
TA1CTL |= ID_3+TAIDEX_3;
Is it fair to assume that now input clock source will be divided by 8 initially by ID_3 which makes clock 4K. And then TAIDEX_3 will further divide this 4K clock by 4
which makes timer clock 1KHz clock.
If we put count = 1K now , then it will produce same 1sec interrupt.
But we are not seeing any interrupt. Whats the problem ? How could we use these two dividers in combinations ?
Example code Code :
int main(void)
{
WDTCTL = WDTPW + WDTHOLD; // Stop WDT
P2DIR |= BIT6; // P2.6 output
TA1CCTL0 = CCIE; // CCR0 interrupt enabled
TA1CTL |= TACLR; //clear TAR
TA1CTL |= TASSEL_1 ; //ACLK
TA1CTL |= ID_3+TAIDEX_3; //Clock Divider (by 8)
// TA1CTL |= TAIDEX_0; //Extended Clock Divider (by 0). Setting this bit other than 0 is causing timer to stop.
TA1CTL |= MC_1; //Mode Control ( Upmode)
TA1CCR0 = 10;
TA1CTL |= TACLR; //clear TAR
__bis_SR_register(LPM3_bits + GIE); // Enter LPM3, enable interrupts
__no_operation(); // For debugger
}
// Timer A0 interrupt service routine
#if defined(__TI_COMPILER_VERSION__) || defined(__IAR_SYSTEMS_ICC__)
#pragma vector=TIMER1_A0_VECTOR
__interrupt void TIMER1_A0_ISR(void)
#elif defined(__GNUC__)
void __attribute__ ((interrupt(TIMER1_A0_VECTOR))) TIMER1_A0_ISR (void)
#else
#error Compiler not supported!
#endif
{
P2OUT ^= BIT6; // Toggle P1.0
}
