Simple count display on LCD with MSP430FR4133 LaunchPad

Show the relevant part of your code.

This works, but would like to count in decimal and just convert it to the display.

 

LCDM0 = 0x21; // L0 = COM0, L1 = COM1

LCDM1 = 0x84; // L2 = COM2, L3 = COM3

Ctr=0;

pos=pos6;

for (;;) { // Loop forever

　

if ((P2IN & SW1) == 0) { // Loop while button down

//LCDMEMCTL |= LCDCLRM; // Clear LCD memory

LCDMEM[pos] = digit[Ctr];

Ctr+=1;

i=50000;

LCDCTL0 |= LCD4MUX | LCDON; // Turn on LCD, 4-mux selected

PMMCTL0_H = PMMPW_H; // Open PMM Registers for write

PMMCTL0_L |= PMMREGOFF_L; // and set PMMREGOFF

if(Ctr>9)

{

Ctr=0;

LCDMEM[pos] = digit[Ctr];

LCDCTL0 |= LCD4MUX | LCDON; // Turn on LCD, 4-mux selected

PMMCTL0_H = PMMPW_H; // Open PMM Registers for write

PMMCTL0_L |= PMMREGOFF_L; // and set PMMREGOFF

}

if(Ctr==0)

{

pos=pos5;

Ctr=1;

LCDMEM[pos] = digit[Ctr];

LCDCTL0 |= LCD4MUX | LCDON; // Turn on LCD, 4-mux selected

PMMCTL0_H = PMMPW_H; // Open PMM Registers for write

PMMCTL0_L |= PMMREGOFF_L; // and set PMMREGOFF

pos=pos6;

}

while (i!=0)

{

i-=1;

}

}

}

A more general solution that takes a binary value and shows it as separate decimal digits would be a bit more complex than your code. A simple way would be to 'print' the value into a string using sprintf (include the header file stdio.h).
unsigned char buffer[6];
sprintf(buffer,"%5u",Cnt);
Then you go through buffer[x] and find a space or 0..9 for 5 digits, buffer[0] being the 10000's, buffer[4] being the 1's Cnt may be an unsigned int. If it is a space (32), put a blank into the position, else subtract 48 from the value in buffer[x] for a binary value of 0...9 that you can use to store into the proper position.
If you use "%05u", then you will get trailing zeros, which spares you checking for space, but looks less nice on the display.