UCBxBRW Register

Stefan Hofmann

Prodigy 20 points

in the code example MSP430FR57xx_uscib0_i2c_10.c the UCBxBRW register is set in this line:

UCB0BRW = 0x0008; // baudrate = SMCLK / 8

In the family datasheet slau272c-1.pdf (Page 527) The description for UCBxBRW is:

fBitClock = fBRCLK/(UCBRx+1)

Wich one is right? According to the family datasheet the line should be

UCB0BRW = 0x0007; // baudrate = SMCLK / 8

or if just the comment is wrong:

UCB0BRW = 0x0008; // baudrate = SMCLK / 9

over 9 years ago

0 Dennis Eichmann over 9 years ago

Guru 74080 points

I remember submitting this to TI a while back as well. But it is

fBRCLK / UCBR

Make your own experience and test both variants while looking at CLK on the scope.

0 Dennis Eichmann over 9 years ago in reply to Dennis Eichmann

Guru 74080 points

0 Stefan Hofmann over 9 years ago

Prodigy 20 points

Thank you, i checked it with the scope, the code example is right. The error is in the datasheet.

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UCBxBRW Register