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UCC12050: UCC12050 power dissipation with 50mA of load

adamo tizzoni
Prodigy 10 points
Part Number: UCC12050

Can confirm that the UCC12050 has a power dissipation of 385 mW with only 50 mA of current load (Iiso) ?

Below my technical analisys.

The following table is taken from datasheet of UCC12050, Power Ratings

Defining Pboard the board power consumption, Pload the load dissipation power and  Pucc the power dissipation of UCC than :

Pboard = Pload + Pucc

If ɳ is the efficiency of DC-DC converter than

Pboard = Viso x Iiso + (1-ɳ) x Pboard

When Iiso = 135mA, with Viso = 3.3Vdc then Pload = 445.5 mW and ɳ = 50%  (full load in Figure 6-14)

In my case with a load current of 50mA the efficiency of ICC12050 is less of 30%

Therefore

Pload = 0.05 x 3.3 = 165 mW, 

Pboard  = Pload/ ɳ = 0.165/0.3 = 550mW,

Pucc = Pboard – Pload =  0.550 – 0.165 = 385 mW

How can improve the efficiency of UCC12050 ?

  • 0
    TI__Mastermind 29505 points

    Hi Adamo,

    The UCC12050 is a complete DC/DC module and so let's keep it as simple as PIN=POUT/η=(3.3V*50mA)/0.3=165mW/0.3=550mW. The power dissipated by UCC12050 is then 550mW-165mW=385mW. I agree with your analysis but since we can't change the frequency or power stage, there is nothing that can be done to "improve the efficiency" What are you biasing with 3.3V, 50mA and what is your greatest concern about the power dissipation - are you planning to operate in a high ambient temp?

    Regards,

    Steve M