BQ24800: BQ24800 ACOK always high issues

Hello Johnny,

ACOK is an active high AC adapter detection open drain output. It is pulled high when a valid adapter is present , that is, when the following conditions are met:

ACDET above 2.4 V, VCC above UVLO but below ACOV and VCC above BAT.

If any of the above conditions is not valid, ACOK is pulled LOW by internal MOSFET

Are there any issues in your system when using this feature?

Sincerely,

Adriana Gonzalez Vega

Hello ,

Have high status of ACOK pin , but do not have any output voltage of charger. The same system can't work without voltage from charger.

Hello Johnny, 

In order for the charger to output voltage, certain parameters need to be set. Charge Current and Charge Voltage must be set correct via a host controller in order for the charger to function properly. For more information, please refer to our User Guide that I have attached below. 

https://www.ti.com/lit/ug/sluuc60/sluuc60.pdf?ts=1656105872764&ref_url=https%253A%252F%252Fwww.google.com%252F

Sincerely,

Adriana Gonzalez Vega

Hello : 

Charger voltage / current : 5V/2A

Connecting a battery to the battery terminal & have an adpater :

BATDRV & BATSRC are the same voltage with battery (4.4V). 

BATPRES# : always 2.56V ( battery is present or absent )

BATSTAT# : always high.

Which registers need to set  except for charge voltage & current? 

Thanks a lot ....

Would you please help to review my charger circuit ( attach file) ? BQ24800 schematic (TI).pdf

Hello 

The signals of BATPRES# is  High and low switching alterntely. Why has this issues?

thanks 

Hello Johnny,

Could you please clarify what parameters are being set. What values are set for VIN, Charge Voltage, Charge Current Registers, etc? BATPRES is an active low pin, if battery is present, the reading should be low consistently. Your adapter voltage might not be high enough, please provide additional information. Thank you

Sincerely,

Adriana Gonzalez Vega

Hi Adriana Gonzalez Vega,

My adapter is 5V/2A ,

 --------------------------------------------------------

battery spec :

Voltage : 4.4V±0.025, Cut off ≦152mA
Charge current : 1,520mA
Discharged current 1,520mA to 3.0V end.

-----------------------------------------------------------------

Registers setting

0x12H Options Control 0: 0xE108

0x14H Charge Current Setting: 0x05C0 (1472mA)

0x15H Charge Voltage Setting: 0x1130 (4.4V)

----------------------------------------------------------------------

Hello,

Voltage of BATDRV & BATSRC are Zero voltage at adapter only condictions? 

Today is a US holiday, please check it back after Tuesday.

Hello Johnny,

I am trying to recreate the issue that you are having, this is requiring more time than anticipated. I will update you on my findings by latest Wednesday, thank you for your patience.

Sincerely,

Adriana Gonzalez Vega

Hello,

Thanks !  Update my status.

BATPRES#: active low.

ACDRV:10.5V  but BATDRV is 4.05V same with my battery volatge. 

My adapter is 5V/2A ,

 --------------------------------------------------------

battery spec :

Voltage : 4.4V±0.025, Cut off ≦152mA
Charge current : 1,520mA
Discharged current 1,520mA to 3.0V end.

-----------------------------------------------------------------

Registers setting

0x12H Options Control 0: 0xE108

0x14H Charge Current Setting: 0x05C0 (1472mA)

0x15H Charge Voltage Setting: 0x1130 (4.4V)

----------------------------------------------------------------------

Hello Johnny,

What I can recommend to debug is to capture a waveform of the switching node, if the capture is switching, then the charger is functioning. On the first waveform, Vin is shown to be 20V, can you please verify the value of Vin. If ACDET is 2.45V, Vin should be closer to 20V. I would also advise to verify the values of the resistor-divider on ACDET. Using 866kOhm and 133kOhm resistors for this resistor-divider will require ~17V for the charger to charge. 

Sincerely,

Adriana Gonzalez Vega

Hello,

Current condiction : 5V/2A . Vin=5V. ACDET=2.45 , BATPRES# is active low.  BATSTAT# is low.

Issues :　BATDRV & BATSRC are the same voltage instead of V(BATDRV) - V(BATSRC) = 6V.

How to turn on BATFET?

thanks 

Hello ,

Register map , BATDRV , BATSRC , HI/LODRV , Vsystem and VPHASE signals.

Hello ,

Disable Watchdog  : VBATDRV:4.14V & VBATSRC:4.14V

Remove Adapter & battery only : VBATDRV:4.14V & VBATSRC:4.14V