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BQ76952: How to calibration CC2 gain

Part Number: BQ76952

Dear Expert

The test data are as follows:

The detection resistance is known to be 1 milliohm, CC Gain = 7.4768 / Rsense (in mOhm);

The estimated CC Gain value is 7.4768.

CCA_para.Current indicates that the external current is 1A. The actual data is 107 (unit: 10mA)

CCA_para.CC2_Counts Indicates that the CC2 count read by 1A is 36306

CCB_para.Current Indicates that the external current is 2A. The actual data is 212 (unit: 10mA)

CCB_para.CC2_Counts Indicates that the CC2 count read by 2A is 72355

The further calibration value is

CC Gain = (212-107)/(72355-36306) = 0.00291270215539959499570029681822.

The value of 7.4768 can not be calculated by other units, which is quite different from the estimated CC Gain.

  • Hi Gabriel,

    I see two issues:

    • The currents in your calculation should be in mA. So it should be (2120-1070)
    • The Counts values you are reading seem way too big. If you see the code example and results in the Calibration application report (https://www.ti.com/lit/an/sluaa32a/sluaa32a.pdf), you will see the values are much smaller for the same currents you are using. See the code example to make sure you are reading the correct bits from the correct register.

    Best regards,

    Matt