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TPS61032 - How to use it for 5V, 3A application ?

Lava Kumar
Prodigy 110 points
Other Parts Discussed in Thread: TPS61032, TPS43000

Dear All,

             I am using DC/DC Converter TPS61032 in my design.

My entire system will consume 2.5A current. I am using battery as well as AC input and which are giving input to BQ24032 Battery charger IC and this output is connected to DC/DC converter TPS61032.

i.e TPS61032 IC has input range from3.5V to 4.4V. The desired output is 5V,3A.  But it is not giving sufficient current.

I have provided resistive network R3 = 900K and R4 =100K.

 

After that I amde a test circuit to test externally by giving 5V input from DC Power supply and Output connected to my board directly. still it is giving not  more than 400mA. 

I have provided the test circuit with values as an attachment.

Kindly suggest me if I am wrong,

Please give me the solution to acheive 5V,3A.

Is there any fixed value  solution for this.

 

0677.TPS61032.docx

 

  • 0
    TI__Guru**** 166696 points

    A boost converter requires higher input current than the output current it provides.  You can do a simple efficiency balance with Pout/Pin=efficiency to quickly confirm.  With 5V*3A / (3.5V *In) = 0.95, Iin needs to be 4.5A.  But the TPS61032 minimum switch current limit is 3.6A.   Alternatively, as datasheet figure 2 shows, with Vin=3.5V, the TPS61032 cannot provide 3A output current. 

    For your test circuit, what was the output load on the TPS61032?  Datasheet figure 12 shows the minimum allowed load resistance into which the TPS61032 can startup.

    You might consider changing to a the TPS43000 controller with external FET.  Or placing two TPS61032 in parallel with a ballast resistor between them as explained in the app note here:  http://www.ti.com/litv/pdf/slva250