Here is the design value.


My design of the outout current is only 0.42A.
The output ripple of Vout is ±7.5%.
But the value of Cout is 32.25uF.
Cout = I * dt / dv = 0.42 * 0.385 / 440k / 0.15 = 2.45uF.
I think there is something wrong.
This thread has been locked.
If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.
Here is the design value.


My design of the outout current is only 0.42A.
The output ripple of Vout is ±7.5%.
But the value of Cout is 32.25uF.
Cout = I * dt / dv = 0.42 * 0.385 / 440k / 0.15 = 2.45uF.
I think there is something wrong.
Hi Lin,
Thanks for reaching out. Determining the output capacitance can be done in multiple ways. Using the output voltage ripple is not the best way to do so.
Most probably, our SEPIC Quick Start Calculator determines the output capacitances based on the load step response voltage deviation, i.e. that when a load step happens, the voltage only changes by x%. If one does it in this way, one can also make sure the voltage ripple in normal operation remains within the designated range.
Thank you and best regards,
Bryan
Hi Lin,
Thanks for the feedback.
I'm not sure what you mean by compensation frequency. It would be great if you could a different explanation.
Furthermore, we've given you some answers in your other thread, maybe that already answers your question.
Thank you and best regards,
Bryan
Hi Lin,
it looks like this thread is identical to this one:
So, i will close this one an put my response on the other thread.
Best regards,
Stefan