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Original question:

LM63635-Q1: Chips are burning out

LM63635-Q1: DESIGN REVIEW

Shubham Yadav
Intellectual 275 points
Part Number: LM63635-Q1
Other Parts Discussed in Thread: LMR43610-Q1

Tool/software:

Dear Sir,

We have selected the LM63635DQPWPRQ1 buck converter for our application dealing with 28 volt input via a power adapter. I have selected switching frequency as 400 kHz and output inductor of value 10uH. I have attached the schematic pdf for your reference please review it and let me know if my design is proper. My output load operating at 3.3V consuming current of approximately 700 mA. Could you please check my design whether component value selected and value all are proper. As my IC stated as o/p current of 3.25A but my load is consuming 700mA of current. Does my efficiency will get reduced? 

Waiting for your response,

Thanks & Regards,
Shubham0647.Sheet1.pdf

  • 0
    TI__Mastermind 24115 points

    Hi Shubham,

    I reviewed your schematic and did not find any glaring issues. 

    Is your concern that this device is not the best part for your output current range as the device is rated for 3.25 A but your load is only 700 mA? Our parts will be optimized for efficiency around different loading conditions. A 1 A part or a 2 A part would likely have better efficiency at your lower load.

    For example, the LM63635-Q1 datasheet has an approximate efficiency around 88% for similar loading conditions (VIN = 24 V, VOUT = 3.3 V, 400 kHz, 700 mA). On the other hand, for the LMR43610-Q1, the datasheet has an approximate efficiency of 92.5% for similar loading conditions (VIN = 24 V, VOUT = 3.3 V, 400 kHz, 700 mA). The LMR43610-Q1 is a 1 A part and is designed to reach optimal efficiency for loads near 1 A. 

    Thank you,

    Joshua Austria