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Original question:

LM2596: Inductor selection

LM2596: Output capacitor and Inductance determination.

afework kassaye
Prodigy 40 points
Part Number: LM2596

If the maximum output current is less than 0.6 Amps, do I have to assume 0.6 Amp is the maximum output current as there is no a lookup graph to find the inductor value.

  • 0
    TI__Expert 4555 points

    Hello,

    I would recommend visiting section 9.1.5 and 9.1.6 starting from page 17 of the datasheet. There is a comprehensive look-up table given on page 19 for appropriate inductor selection. 

    Best Regards,

    Ankit Gupta

    Application Engineer.

      

  • 0 in reply to Ankit Gupta95
    Prodigy 40 points

    If you see on page 19 of the data sheet the minimum  maximum load current shown is 0.6 Amps. In my design my maximum load current is 0.25 Amps so, I am not sure what max. load current to use in order to select the inductor value.

  • 0 in reply to afework kassaye
    TI__Expert 4555 points

    Hello Afework,

    Looks like your application is of the discontinuous mode of operation, which is helpful for light-load efficiency. I would recommend you using an inductor smaller than 15uH. I normally recommend inductors to have saturation current higher than part's current limit, because your inductor should not saturate during the current-limit protection scenario. So I would recommend having an inductor less than 15uH and Isat greater than 6.9A. And I would recommend double-checking the stability of your design on the Webench. Hope this helps!

    Please close the thread if you think my response answered your question.

    Best Regards,

    Ankit Gupta

    Application Engineer