...solder an 8.2K ohm resistor across Rfb2 (10K) and then a 560K ohm across Rfb1 (29.4k) ohm resistor. Rfb2 actually has a few thru-holes in parallel with it, so it's novice-easy, but Rfb2 has none so it'll be a little trickier. It'll yield -9.04V on Vout. I think a single 9.1K ohm resistor across Rfb2 (10K) would also yield close results, but I didn't have one of those. Give it a shot and report, please.
Also, since Cin is only a 6.3V cap, you'll want to keep the soldering iron hot and replace that one with a higher voltage cap. With these hacks you can connect +9V, say from a 9V alkaline battery, and you are good to go with a nice clean +/-9V supply.
And yes, it is a glaring omission on the datasheet that there isn't an easy formula, or chart, given to help designers achieve other negative voltages. Someone on another thread pointed an inquiring designer to TI's Power Stage Design Tool, but it also comes up short on this area. I tried it. It'll only help with selecting inductors and caps. Important? Yes, but not fully helpful.