Other Parts Discussed in Thread: LMR14020
Hello,
I'm planning to use LMR14020-Q1, where my nominal input voltage will be 12V and I'm planning to set the output voltage at 3.8V.
I'm using L=4.7uH , and 2 x 22uF as Cout , fsw 1.8MHz , Cin =10uF
In normal cases i may see a load current requirement up to 1.5 - 2A.
But in say a system low power mode the 3.8V output only requires round 3.4mA.
I understand the LMR14020-Q1 will be in sleep mode at this condition. I want to precisely know how much will be my input current in this situation.
Also if possible how that will be calculated.
Can i go like this say output power is 3.8V x 3.4 mA = 12.92 mW; considering approximately 70% efficiency, Pin= 18.457mW ; with 12V input can i expect Input current =~ 1.53 mA continuous ?
Also do i need to add the standby current or any other pin current to this figure.?
If you can confirm this soon , it will be really helpful.
Awaiting your response.
Thanks
Stephen