Defining a structure and allocating memory for the structure ?

Hi Raju,

The code snippet you sketched above has an issue with the allocation of the memory for the Sample structure. In your IALG::algAlloc function, the 'size' of memTab[1] structure should be the size of the Sample structure. You are incorrectly setting that to the size of a pointer-to-Sample-structure.

 If you changed that to something like:

<module>_<vendor>_alloc(const IALG *algParams, IALG_Fxns **pf, IALG_MemRec memTab[])
{
   . . .
   memTab[0].size = sizeof(<module>_<vendor>_obj);
   . . .
   memTab[1].size = sizeof(Sample) * numSamples; /* numSamples is defined by your algo, this is the number of Samples */

}

But even this does not allocate memory for the 'ptr' array that you reference within the Sample struct. I am not sure what you are trying to do, but if you need to allocate an array for the 'ptr', that should also be requested by algAlloc(). For example:

<module>_<vendor>_alloc(const IALG *algParams, IALG_Fxns **pf, IALG_MemRec memTab[])
{
   . . .
   memTab[0].size = sizeof(<module>_<vendor>_obj);
   . . .
   memTab[1].size = sizeof(Sample);
   memTab[2].size = sizeof(<whatever-size-of-ptr-array should be>);

}

Using this allocation logic, inside your algInit() code, you can initialize the 'ptr' field to the memory allocated via memTab[2]. E.g. :

   obj->st_ptr         = memTab[1].base;
   obj->st_ptr->ptr = memTab[2].base;

Hope this helps,

Murat